Base | Representation |
---|---|
bin | 110101110000110011… |
… | …1100101101100110111 |
3 | 102001000012211021101100 |
4 | 1223201213211230313 |
5 | 3342422311320320 |
6 | 125012232301143 |
7 | 11225032135110 |
oct | 1534147455467 |
9 | 361005737340 |
10 | 115454401335 |
11 | 44a66aaa609 |
12 | 1a4615417b3 |
13 | ab6c536910 |
14 | 583376b207 |
15 | 300adab790 |
hex | 1ae19e5b37 |
115454401335 has 48 divisors (see below), whose sum is σ = 246302731584. Its totient is φ = 48719218176.
The previous prime is 115454401261. The next prime is 115454401357. The reversal of 115454401335 is 533104454511.
It is not a de Polignac number, because 115454401335 - 29 = 115454400823 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 115454401335.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 14092902 + ... + 14101091.
It is an arithmetic number, because the mean of its divisors is an integer number (5131306908).
Almost surely, 2115454401335 is an apocalyptic number.
115454401335 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
115454401335 is an abundant number, since it is smaller than the sum of its proper divisors (130848330249).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
115454401335 is a wasteful number, since it uses less digits than its factorization.
115454401335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 28194024 (or 28194021 counting only the distinct ones).
The product of its (nonzero) digits is 72000, while the sum is 36.
Adding to 115454401335 its reverse (533104454511), we get a palindrome (648558855846).
The spelling of 115454401335 in words is "one hundred fifteen billion, four hundred fifty-four million, four hundred one thousand, three hundred thirty-five".
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