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115461143079193 is a prime number
BaseRepresentation
bin11010010000001011100100…
…011010110010100100011001
3120010210222101120201112010201
4122100023210122302210121
5110113203410112013233
61045322041124542201
733214535522005102
oct3220134432624431
9503728346645121
10115461143079193
113387588322545a
1210b49187251961
134c56c291b5b52
1420724c60933a9
15d536215c577d
hex6902e46b2919

115461143079193 has 2 divisors, whose sum is σ = 115461143079194. Its totient is φ = 115461143079192.

The previous prime is 115461143079151. The next prime is 115461143079209. The reversal of 115461143079193 is 391970341164511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 100288848282624 + 15172294796569 = 10014432^2 + 3895163^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-115461143079193 is a prime.

It is a super-2 number, since 2×1154611430791932 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (115461143079493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57730571539596 + 57730571539597.

It is an arithmetic number, because the mean of its divisors is an integer number (57730571539597).

Almost surely, 2115461143079193 is an apocalyptic number.

It is an amenable number.

115461143079193 is a deficient number, since it is larger than the sum of its proper divisors (1).

115461143079193 is an equidigital number, since it uses as much as digits as its factorization.

115461143079193 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2449440, while the sum is 55.

The spelling of 115461143079193 in words is "one hundred fifteen trillion, four hundred sixty-one billion, one hundred forty-three million, seventy-nine thousand, one hundred ninety-three".