115463062543753 has 2 divisors, whose sum is σ = 115463062543754. Its totient is φ = 115463062543752.

The previous prime is 115463062543733. The next prime is 115463062543897. The reversal of 115463062543753 is 357345260364511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 63832557662784 + 51630504880969 = 7989528^2 + 7185437^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-115463062543753 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 115463062543694 and 115463062543703.

It is not a weakly prime, because it can be changed into another prime (115463062543733) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57731531271876 + 57731531271877.

It is an arithmetic number, because the mean of its divisors is an integer number (57731531271877).

Almost surely, 2^{115463062543753} is an apocalyptic number.

It is an amenable number.

115463062543753 is a deficient number, since it is larger than the sum of its proper divisors (1).

115463062543753 is an equidigital number, since it uses as much as digits as its factorization.

115463062543753 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 27216000, while the sum is 55.

The spelling of 115463062543753 in words is "one hundred fifteen trillion, four hundred sixty-three billion, sixty-two million, five hundred forty-three thousand, seven hundred fifty-three".