Base | Representation |
---|---|
bin | 10101100000100110… |
… | …00110000010001001 |
3 | 1002210210002110121211 |
4 | 22300103012002021 |
5 | 142122204330212 |
6 | 5145511533121 |
7 | 556110041323 |
oct | 126023060211 |
9 | 32723073554 |
10 | 11547730057 |
11 | 4996435566 |
12 | 22a338a1a1 |
13 | 1120551886 |
14 | 7b792c613 |
15 | 478bd49a7 |
hex | 2b04c6089 |
11547730057 has 2 divisors, whose sum is σ = 11547730058. Its totient is φ = 11547730056.
The previous prime is 11547730049. The next prime is 11547730093. The reversal of 11547730057 is 75003774511.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9812091136 + 1735638921 = 99056^2 + 41661^2 .
It is a cyclic number.
It is not a de Polignac number, because 11547730057 - 23 = 11547730049 is a prime.
It is not a weakly prime, because it can be changed into another prime (11547730457) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5773865028 + 5773865029.
It is an arithmetic number, because the mean of its divisors is an integer number (5773865029).
Almost surely, 211547730057 is an apocalyptic number.
It is an amenable number.
11547730057 is a deficient number, since it is larger than the sum of its proper divisors (1).
11547730057 is an equidigital number, since it uses as much as digits as its factorization.
11547730057 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 102900, while the sum is 40.
The spelling of 11547730057 in words is "eleven billion, five hundred forty-seven million, seven hundred thirty thousand, fifty-seven".
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