Base | Representation |
---|---|
bin | 11010010000101111111000… |
… | …100001101101011001101001 |
3 | 120010221201001000011121010201 |
4 | 122100233320201231121221 |
5 | 110114323234044034032 |
6 | 1045352010220112201 |
7 | 33220416010042342 |
oct | 3220577041553151 |
9 | 503851030147121 |
10 | 115500135143017 |
11 | 3389037222a099 |
12 | 10b54849695661 |
13 | 4c5a8014acb71 |
14 | 20743448490c9 |
15 | d5465485e8e7 |
hex | 690bf886d669 |
115500135143017 has 2 divisors, whose sum is σ = 115500135143018. Its totient is φ = 115500135143016.
The previous prime is 115500135142943. The next prime is 115500135143087. The reversal of 115500135143017 is 710341531005511.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 66825736439401 + 48674398703616 = 8174701^2 + 6976704^2 .
It is a cyclic number.
It is not a de Polignac number, because 115500135143017 - 215 = 115500135110249 is a prime.
It is not a weakly prime, because it can be changed into another prime (115500135143087) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57750067571508 + 57750067571509.
It is an arithmetic number, because the mean of its divisors is an integer number (57750067571509).
Almost surely, 2115500135143017 is an apocalyptic number.
It is an amenable number.
115500135143017 is a deficient number, since it is larger than the sum of its proper divisors (1).
115500135143017 is an equidigital number, since it uses as much as digits as its factorization.
115500135143017 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 31500, while the sum is 37.
Adding to 115500135143017 its reverse (710341531005511), we get a palindrome (825841666148528).
The spelling of 115500135143017 in words is "one hundred fifteen trillion, five hundred billion, one hundred thirty-five million, one hundred forty-three thousand, seventeen".
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