Base | Representation |
---|---|
bin | 1010100000010101000101… |
… | …1110100110011011001111 |
3 | 1111220012221120120100200110 |
4 | 2220011101132212123033 |
5 | 3003220443203111101 |
6 | 40322124142331103 |
7 | 2301333000235356 |
oct | 250052136463317 |
9 | 44805846510613 |
10 | 11550534035151 |
11 | 3753610382a21 |
12 | 13666a2589a93 |
13 | 65a297b52477 |
14 | 2bd097dc099d |
15 | 1506c89becd6 |
hex | a81517a66cf |
11550534035151 has 32 divisors (see below), whose sum is σ = 15581051179200. Its totient is φ = 7610849132544.
The previous prime is 11550534035123. The next prime is 11550534035153. The reversal of 11550534035151 is 15153043505511.
11550534035151 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11550534035151 - 25 = 11550534035119 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11550534035153) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 61558825 + ... + 61746173.
It is an arithmetic number, because the mean of its divisors is an integer number (486907849350).
Almost surely, 211550534035151 is an apocalyptic number.
11550534035151 is a deficient number, since it is larger than the sum of its proper divisors (4030517144049).
11550534035151 is a wasteful number, since it uses less digits than its factorization.
11550534035151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 188235.
The product of its (nonzero) digits is 112500, while the sum is 39.
The spelling of 11550534035151 in words is "eleven trillion, five hundred fifty billion, five hundred thirty-four million, thirty-five thousand, one hundred fifty-one".
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