Base | Representation |
---|---|
bin | 10101100001000001… |
… | …01011110001000011 |
3 | 1002211000210110100112 |
4 | 22300200223301003 |
5 | 142124112324413 |
6 | 5150120141535 |
7 | 556152236363 |
oct | 126040536103 |
9 | 32730713315 |
10 | 11551292483 |
11 | 4998449015 |
12 | 22a46078ab |
13 | 11211cb213 |
14 | 7b81b89a3 |
15 | 47918a2a8 |
hex | 2b082bc43 |
11551292483 has 2 divisors, whose sum is σ = 11551292484. Its totient is φ = 11551292482.
The previous prime is 11551292479. The next prime is 11551292491. The reversal of 11551292483 is 38429215511.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11551292483 - 22 = 11551292479 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11551292483.
It is not a weakly prime, because it can be changed into another prime (11551292453) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5775646241 + 5775646242.
It is an arithmetic number, because the mean of its divisors is an integer number (5775646242).
Almost surely, 211551292483 is an apocalyptic number.
11551292483 is a deficient number, since it is larger than the sum of its proper divisors (1).
11551292483 is an equidigital number, since it uses as much as digits as its factorization.
11551292483 is an evil number, because the sum of its binary digits is even.
The product of its digits is 86400, while the sum is 41.
The spelling of 11551292483 in words is "eleven billion, five hundred fifty-one million, two hundred ninety-two thousand, four hundred eighty-three".
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