Base | Representation |
---|---|
bin | 10101100001000110… |
… | …11101111011101011 |
3 | 1002211002011112101222 |
4 | 22300203131323223 |
5 | 142124304203001 |
6 | 5150143532255 |
7 | 556161366110 |
oct | 126043357353 |
9 | 32732145358 |
10 | 11552022251 |
11 | 49988a7330 |
12 | 22a48ba08b |
13 | 11213c5433 |
14 | 7b8328907 |
15 | 47928161b |
hex | 2b08ddeeb |
11552022251 has 32 divisors (see below), whose sum is σ = 15040512000. Its totient is φ = 8603448480.
The previous prime is 11552022239. The next prime is 11552022263. The reversal of 11552022251 is 15222025511.
It is a happy number.
It is an interprime number because it is at equal distance from previous prime (11552022239) and next prime (11552022263).
It is not a de Polignac number, because 11552022251 - 214 = 11552005867 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 11552022251.
It is not an unprimeable number, because it can be changed into a prime (11552022551) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4247270 + ... + 4249988.
It is an arithmetic number, because the mean of its divisors is an integer number (470016000).
Almost surely, 211552022251 is an apocalyptic number.
11552022251 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
11552022251 is a deficient number, since it is larger than the sum of its proper divisors (3488489749).
11552022251 is a wasteful number, since it uses less digits than its factorization.
11552022251 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5159.
The product of its (nonzero) digits is 2000, while the sum is 26.
Adding to 11552022251 its reverse (15222025511), we get a palindrome (26774047762).
The spelling of 11552022251 in words is "eleven billion, five hundred fifty-two million, twenty-two thousand, two hundred fifty-one".
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