Base | Representation |
---|---|
bin | 1010100000011011000001… |
… | …0101101110011001011011 |
3 | 1111220101001111021101102122 |
4 | 2220012300111232121123 |
5 | 3003232223114402102 |
6 | 40322550114051455 |
7 | 2301420303652055 |
oct | 250066025563133 |
9 | 44811044241378 |
10 | 11552125544027 |
11 | 3754257785112 |
12 | 1366a67579b8b |
13 | 65a48c7a43b3 |
14 | 2bd1a95048d5 |
15 | 15076d5930a2 |
hex | a81b056e65b |
11552125544027 has 2 divisors, whose sum is σ = 11552125544028. Its totient is φ = 11552125544026.
The previous prime is 11552125543999. The next prime is 11552125544041. The reversal of 11552125544027 is 72044552125511.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11552125544027 is a prime.
It is a super-2 number, since 2×115521255440272 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11552125594027) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5776062772013 + 5776062772014.
It is an arithmetic number, because the mean of its divisors is an integer number (5776062772014).
Almost surely, 211552125544027 is an apocalyptic number.
11552125544027 is a deficient number, since it is larger than the sum of its proper divisors (1).
11552125544027 is an equidigital number, since it uses as much as digits as its factorization.
11552125544027 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 560000, while the sum is 44.
Adding to 11552125544027 its reverse (72044552125511), we get a palindrome (83596677669538).
The spelling of 11552125544027 in words is "eleven trillion, five hundred fifty-two billion, one hundred twenty-five million, five hundred forty-four thousand, twenty-seven".
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