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11553330552217 is a prime number
BaseRepresentation
bin1010100000011111100000…
…1010011101110110011001
31111220111011110201010220121
42220013320022131312121
53003242210110132332
640323305441353241
72301462205236346
oct250077012356631
944814143633817
1011553330552217
1137548159a1653
121367143038821
1365a6223302ac
142bd2815797cd
151507de26c797
hexa81f829dd99

11553330552217 has 2 divisors, whose sum is σ = 11553330552218. Its totient is φ = 11553330552216.

The previous prime is 11553330552143. The next prime is 11553330552223. The reversal of 11553330552217 is 71225503335511.

11553330552217 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9878128416601 + 1675202135616 = 3142949^2 + 1294296^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11553330552217 is a prime.

It is not a weakly prime, because it can be changed into another prime (11553330552017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5776665276108 + 5776665276109.

It is an arithmetic number, because the mean of its divisors is an integer number (5776665276109).

Almost surely, 211553330552217 is an apocalyptic number.

It is an amenable number.

11553330552217 is a deficient number, since it is larger than the sum of its proper divisors (1).

11553330552217 is an equidigital number, since it uses as much as digits as its factorization.

11553330552217 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 472500, while the sum is 43.

Adding to 11553330552217 its reverse (71225503335511), we get a palindrome (82778833887728).

The spelling of 11553330552217 in words is "eleven trillion, five hundred fifty-three billion, three hundred thirty million, five hundred fifty-two thousand, two hundred seventeen".