Base | Representation |
---|---|
bin | 11010010001001111111011… |
… | …011010100010101011000011 |
3 | 120011001222211222020210211121 |
4 | 122101033323122202223003 |
5 | 110120404221043142313 |
6 | 1045415500403053111 |
7 | 33223044454613236 |
oct | 3221177332425303 |
9 | 504058758223747 |
10 | 115534543334083 |
11 | 338a3a19807335 |
12 | 10b5b450971197 |
13 | 4c60b25c15333 |
14 | 2075c8a50141d |
15 | d554ba48e28d |
hex | 6913fb6a2ac3 |
115534543334083 has 2 divisors, whose sum is σ = 115534543334084. Its totient is φ = 115534543334082.
The previous prime is 115534543334057. The next prime is 115534543334159. The reversal of 115534543334083 is 380433345435511.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 115534543334083 - 241 = 113335520078531 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 115534543334083.
It is not a weakly prime, because it can be changed into another prime (115534543334783) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57767271667041 + 57767271667042.
It is an arithmetic number, because the mean of its divisors is an integer number (57767271667042).
Almost surely, 2115534543334083 is an apocalyptic number.
115534543334083 is a deficient number, since it is larger than the sum of its proper divisors (1).
115534543334083 is an equidigital number, since it uses as much as digits as its factorization.
115534543334083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15552000, while the sum is 52.
Adding to 115534543334083 its reverse (380433345435511), we get a palindrome (495967888769594).
The spelling of 115534543334083 in words is "one hundred fifteen trillion, five hundred thirty-four billion, five hundred forty-three million, three hundred thirty-four thousand, eighty-three".
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