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115534661321641 is a prime number
BaseRepresentation
bin11010010001010000000010…
…011100101000001110101001
3120011002000011012021012100011
4122101100002130220032221
5110120404441244243031
61045415520220011521
733223050416523262
oct3221200234501651
9504060135235304
10115534661321641
11338a3a7a374111
1210b5b484390ba1
134c60b444b6263
142075c9c055969
15d554c59e86b1
hex6914027283a9

115534661321641 has 2 divisors, whose sum is σ = 115534661321642. Its totient is φ = 115534661321640.

The previous prime is 115534661321617. The next prime is 115534661321647. The reversal of 115534661321641 is 146123166435511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 110220161019241 + 5314500302400 = 10498579^2 + 2305320^2 .

It is an emirp because it is prime and its reverse (146123166435511) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 115534661321641 - 29 = 115534661321129 is a prime.

It is a super-3 number, since 3×1155346613216413 (a number of 43 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (115534661321647) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57767330660820 + 57767330660821.

It is an arithmetic number, because the mean of its divisors is an integer number (57767330660821).

Almost surely, 2115534661321641 is an apocalyptic number.

It is an amenable number.

115534661321641 is a deficient number, since it is larger than the sum of its proper divisors (1).

115534661321641 is an equidigital number, since it uses as much as digits as its factorization.

115534661321641 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1555200, while the sum is 49.

The spelling of 115534661321641 in words is "one hundred fifteen trillion, five hundred thirty-four billion, six hundred sixty-one million, three hundred twenty-one thousand, six hundred forty-one".