Base | Representation |
---|---|
bin | 1010100000100010001110… |
… | …1001111001110011101011 |
3 | 1111220120001022200202222221 |
4 | 2220020203221321303223 |
5 | 3003300203403312413 |
6 | 40323510104454511 |
7 | 2301516245245564 |
oct | 250104351716353 |
9 | 44816038622887 |
10 | 11554060213483 |
11 | 375505a85a997 |
12 | 136730747a437 |
13 | 65a70a556418 |
14 | 2bd31043516b |
15 | 15083334d68d |
hex | a8223a79ceb |
11554060213483 has 2 divisors, whose sum is σ = 11554060213484. Its totient is φ = 11554060213482.
The previous prime is 11554060213417. The next prime is 11554060213547. The reversal of 11554060213483 is 38431206045511.
11554060213483 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11554060213483 - 213 = 11554060205291 is a prime.
It is not a weakly prime, because it can be changed into another prime (11554060213783) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5777030106741 + 5777030106742.
It is an arithmetic number, because the mean of its divisors is an integer number (5777030106742).
Almost surely, 211554060213483 is an apocalyptic number.
11554060213483 is a deficient number, since it is larger than the sum of its proper divisors (1).
11554060213483 is an equidigital number, since it uses as much as digits as its factorization.
11554060213483 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 345600, while the sum is 43.
Adding to 11554060213483 its reverse (38431206045511), we get a palindrome (49985266258994).
The spelling of 11554060213483 in words is "eleven trillion, five hundred fifty-four billion, sixty million, two hundred thirteen thousand, four hundred eighty-three".
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