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11554361552017 is a prime number
BaseRepresentation
bin1010100000100011010110…
…0111011010110010010001
31111220120211022201100202101
42220020311213122302101
53003301313024131032
640324000031320401
72301526564501564
oct250106547326221
944816738640671
1011554361552017
1137551a4968aa9
121367390380101
1365a757b0254b
142bd33c4764db
1515084ea23de7
hexa82359dac91

11554361552017 has 2 divisors, whose sum is σ = 11554361552018. Its totient is φ = 11554361552016.

The previous prime is 11554361551987. The next prime is 11554361552159. The reversal of 11554361552017 is 71025516345511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11529562861441 + 24798690576 = 3395521^2 + 157476^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11554361552017 is a prime.

It is not a weakly prime, because it can be changed into another prime (11554361552417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5777180776008 + 5777180776009.

It is an arithmetic number, because the mean of its divisors is an integer number (5777180776009).

Almost surely, 211554361552017 is an apocalyptic number.

It is an amenable number.

11554361552017 is a deficient number, since it is larger than the sum of its proper divisors (1).

11554361552017 is an equidigital number, since it uses as much as digits as its factorization.

11554361552017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 630000, while the sum is 46.

Adding to 11554361552017 its reverse (71025516345511), we get a palindrome (82579877897528).

The spelling of 11554361552017 in words is "eleven trillion, five hundred fifty-four billion, three hundred sixty-one million, five hundred fifty-two thousand, seventeen".