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11554362110353 is a prime number
BaseRepresentation
bin1010100000100011010110…
…1001100011000110010001
31111220120211100202201122111
42220020311221203012101
53003301313200012403
640324000051305321
72301526602315436
oct250106551430621
944816740681574
1011554362110353
1137551a520a537
1213673905ab241
1365a757c6971a
142bd33c57db8d
1515084ead456d
hexa8235a63191

11554362110353 has 2 divisors, whose sum is σ = 11554362110354. Its totient is φ = 11554362110352.

The previous prime is 11554362110339. The next prime is 11554362110359. The reversal of 11554362110353 is 35301126345511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11349305290129 + 205056820224 = 3368873^2 + 452832^2 .

It is a cyclic number.

It is not a de Polignac number, because 11554362110353 - 221 = 11554360013201 is a prime.

It is a super-2 number, since 2×115543621103532 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (11554362110359) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5777181055176 + 5777181055177.

It is an arithmetic number, because the mean of its divisors is an integer number (5777181055177).

Almost surely, 211554362110353 is an apocalyptic number.

It is an amenable number.

11554362110353 is a deficient number, since it is larger than the sum of its proper divisors (1).

11554362110353 is an equidigital number, since it uses as much as digits as its factorization.

11554362110353 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 162000, while the sum is 40.

Adding to 11554362110353 its reverse (35301126345511), we get a palindrome (46855488455864).

The spelling of 11554362110353 in words is "eleven trillion, five hundred fifty-four billion, three hundred sixty-two million, one hundred ten thousand, three hundred fifty-three".