Base | Representation |
---|---|
bin | 10101100001011011… |
… | …01111010111001011 |
3 | 1002211021020100021111 |
4 | 22300231233113023 |
5 | 142131001340313 |
6 | 5150321351151 |
7 | 556223312662 |
oct | 126055572713 |
9 | 32737210244 |
10 | 11554715083 |
11 | 499a37650a |
12 | 22a57984b7 |
13 | 1121b29022 |
14 | 7b8829dd9 |
15 | 47961443d |
hex | 2b0b6f5cb |
11554715083 has 2 divisors, whose sum is σ = 11554715084. Its totient is φ = 11554715082.
The previous prime is 11554715071. The next prime is 11554715093. The reversal of 11554715083 is 38051745511.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11554715083 - 221 = 11552617931 is a prime.
It is a super-2 number, since 2×115547150832 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11554715063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5777357541 + 5777357542.
It is an arithmetic number, because the mean of its divisors is an integer number (5777357542).
Almost surely, 211554715083 is an apocalyptic number.
11554715083 is a deficient number, since it is larger than the sum of its proper divisors (1).
11554715083 is an equidigital number, since it uses as much as digits as its factorization.
11554715083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 84000, while the sum is 40.
The spelling of 11554715083 in words is "eleven billion, five hundred fifty-four million, seven hundred fifteen thousand, eighty-three".
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