1155531133541 has 4 divisors (see below), whose sum is σ = 1205771617632. Its totient is φ = 1105290649452.

The previous prime is 1155531133531. The next prime is 1155531133571. The reversal of 1155531133541 is 1453311355511.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1155531133541 - 2¹⁰ = 1155531132517 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1155531133495 and 1155531133504.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1155531133531) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25120242011 + ... + 25120242056.

It is an arithmetic number, because the mean of its divisors is an integer number (301442904408).

Almost surely, 2^{1155531133541} is an apocalyptic number.

It is an amenable number.

1155531133541 is a deficient number, since it is larger than the sum of its proper divisors (50240484091).

1155531133541 is an equidigital number, since it uses as much as digits as its factorization.

1155531133541 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 50240484090.

The product of its digits is 67500, while the sum is 38.

The spelling of 1155531133541 in words is "one trillion, one hundred fifty-five billion, five hundred thirty-one million, one hundred thirty-three thousand, five hundred forty-one".