Base | Representation |
---|---|
bin | 10101100010011100… |
… | …01000010111100001 |
3 | 1002211212012201210002 |
4 | 22301032020113201 |
5 | 142140140043423 |
6 | 5151223345345 |
7 | 556355426114 |
oct | 126116102741 |
9 | 32755181702 |
10 | 11563206113 |
11 | 49a4145998 |
12 | 22a85b2255 |
13 | 112380cac4 |
14 | 7b99da57b |
15 | 47a240228 |
hex | 2b13885e1 |
11563206113 has 2 divisors, whose sum is σ = 11563206114. Its totient is φ = 11563206112.
The previous prime is 11563206103. The next prime is 11563206131. The reversal of 11563206113 is 31160236511.
Together with next prime (11563206131) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6218426449 + 5344779664 = 78857^2 + 73108^2 .
It is a cyclic number.
It is not a de Polignac number, because 11563206113 - 210 = 11563205089 is a prime.
It is a super-2 number, since 2×115632061132 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11563206103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5781603056 + 5781603057.
It is an arithmetic number, because the mean of its divisors is an integer number (5781603057).
Almost surely, 211563206113 is an apocalyptic number.
It is an amenable number.
11563206113 is a deficient number, since it is larger than the sum of its proper divisors (1).
11563206113 is an equidigital number, since it uses as much as digits as its factorization.
11563206113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3240, while the sum is 29.
The spelling of 11563206113 in words is "eleven billion, five hundred sixty-three million, two hundred six thousand, one hundred thirteen".
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