Base | Representation |
---|---|
bin | 1010100001001010011010… |
… | …1110000000011011001111 |
3 | 1111221120220012202220101020 |
4 | 2220102212232000123033 |
5 | 3003434302323222210 |
6 | 40332452430445223 |
7 | 2302350511613544 |
oct | 250224656003317 |
9 | 44846805686336 |
10 | 11564849039055 |
11 | 3759696873264 |
12 | 1369418663813 |
13 | 65b7397b3490 |
14 | 2bda55254bcb |
15 | 150c655c7770 |
hex | a84a6b806cf |
11564849039055 has 64 divisors (see below), whose sum is σ = 19965669115392. Its totient is φ = 5682458534400.
The previous prime is 11564849039021. The next prime is 11564849039077. The reversal of 11564849039055 is 55093094846511.
It is not a de Polignac number, because 11564849039055 - 231 = 11562701555407 is a prime.
It is a super-2 number, since 2×115648490390552 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 11564849039055.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 341622880 + ... + 341656730.
It is an arithmetic number, because the mean of its divisors is an integer number (311963579928).
Almost surely, 211564849039055 is an apocalyptic number.
11564849039055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
11564849039055 is a deficient number, since it is larger than the sum of its proper divisors (8400820076337).
11564849039055 is a wasteful number, since it uses less digits than its factorization.
11564849039055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 37208.
The product of its (nonzero) digits is 23328000, while the sum is 60.
The spelling of 11564849039055 in words is "eleven trillion, five hundred sixty-four billion, eight hundred forty-nine million, thirty-nine thousand, fifty-five".
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