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115650130032434 = 257825065016217
BaseRepresentation
bin11010010010111011100100…
…111010110011011100110010
3120011111001012102000110121102
4122102323210322303130302
5110124302431242014214
61045544534123124402
733234306014420054
oct3222734472633462
9504431172013542
10115650130032434
1133938a43457618
1210b7992a673702
134c6b9b69900ba
14207b6d36698d4
15d584d2c7ebde
hex692ee4eb3732

115650130032434 has 4 divisors (see below), whose sum is σ = 173475195048654. Its totient is φ = 57825065016216.

The previous prime is 115650130032401. The next prime is 115650130032439. The reversal of 115650130032434 is 434230031056511.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 108066732115225 + 7583397917209 = 10395515^2 + 2753797^2 .

It is not an unprimeable number, because it can be changed into a prime (115650130032439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28912532508107 + ... + 28912532508110.

Almost surely, 2115650130032434 is an apocalyptic number.

115650130032434 is a deficient number, since it is larger than the sum of its proper divisors (57825065016220).

115650130032434 is an equidigital number, since it uses as much as digits as its factorization.

115650130032434 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 57825065016219.

The product of its (nonzero) digits is 129600, while the sum is 38.

Adding to 115650130032434 its reverse (434230031056511), we get a palindrome (549880161088945).

The spelling of 115650130032434 in words is "one hundred fifteen trillion, six hundred fifty billion, one hundred thirty million, thirty-two thousand, four hundred thirty-four".

Divisors: 1 2 57825065016217 115650130032434