Base | Representation |
---|---|
bin | 10000110101100011001… |
… | …011001110111011100011 |
3 | 11002121110000121111102021 |
4 | 100311203023032323203 |
5 | 122424024040413442 |
6 | 2243304553402311 |
7 | 146406534340366 |
oct | 20654313167343 |
9 | 4077400544367 |
10 | 1157010091747 |
11 | 40675a0407a4 |
12 | 1682a0409397 |
13 | 8514ac75483 |
14 | 3dddcc200dd |
15 | 2016a9a4e67 |
hex | 10d632ceee3 |
1157010091747 has 2 divisors, whose sum is σ = 1157010091748. Its totient is φ = 1157010091746.
The previous prime is 1157010091693. The next prime is 1157010091837. The reversal of 1157010091747 is 7471900107511.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1157010091747 - 231 = 1154862608099 is a prime.
It is not a weakly prime, because it can be changed into another prime (1157010098747) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 578505045873 + 578505045874.
It is an arithmetic number, because the mean of its divisors is an integer number (578505045874).
Almost surely, 21157010091747 is an apocalyptic number.
1157010091747 is a deficient number, since it is larger than the sum of its proper divisors (1).
1157010091747 is an equidigital number, since it uses as much as digits as its factorization.
1157010091747 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 61740, while the sum is 43.
The spelling of 1157010091747 in words is "one trillion, one hundred fifty-seven billion, ten million, ninety-one thousand, seven hundred forty-seven".
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