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115800365335649 is a prime number
BaseRepresentation
bin11010010101000111011111…
…101001000000010001100001
3120012000101222120020121210212
4122111013133221000101201
5110134233122011220044
61050141541535103505
733251205001422401
oct3225073751002141
9505011876217725
10115800365335649
1133996728360535
1210ba2a78071b95
134c7cc09c07617
142084aa638c801
15d5c37733da9e
hex6951dfa40461

115800365335649 has 2 divisors, whose sum is σ = 115800365335650. Its totient is φ = 115800365335648.

The previous prime is 115800365335609. The next prime is 115800365335703. The reversal of 115800365335649 is 946533563008511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 65452258326049 + 50348107009600 = 8090257^2 + 7095640^2 .

It is an emirp because it is prime and its reverse (946533563008511) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-115800365335649 is a prime.

It is a super-2 number, since 2×1158003653356492 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (115800365335609) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57900182667824 + 57900182667825.

It is an arithmetic number, because the mean of its divisors is an integer number (57900182667825).

Almost surely, 2115800365335649 is an apocalyptic number.

It is an amenable number.

115800365335649 is a deficient number, since it is larger than the sum of its proper divisors (1).

115800365335649 is an equidigital number, since it uses as much as digits as its factorization.

115800365335649 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 34992000, while the sum is 59.

The spelling of 115800365335649 in words is "one hundred fifteen trillion, eight hundred billion, three hundred sixty-five million, three hundred thirty-five thousand, six hundred forty-nine".