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115960035071921 is a prime number
BaseRepresentation
bin11010010111011100001100…
…101100101101011110110001
3120012120200010020000122010212
4122113130030230231132301
5110144342122434300141
61050343145451433505
733265556524661525
oct3227341454553661
9505520106018125
10115960035071921
1133a484137a9667
12110099b9155895
134c91ca490b401
14208c6d2091d85
15d615bece02eb
hex69770cb2d7b1

115960035071921 has 2 divisors, whose sum is σ = 115960035071922. Its totient is φ = 115960035071920.

The previous prime is 115960035071873. The next prime is 115960035072017. The reversal of 115960035071921 is 129170530069511.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 71136809221696 + 44823225850225 = 8434264^2 + 6695015^2 .

It is a cyclic number.

It is not a de Polignac number, because 115960035071921 - 230 = 115958961330097 is a prime.

It is a super-2 number, since 2×1159600350719212 (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 115960035071921.

It is not a weakly prime, because it can be changed into another prime (115960035071021) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57980017535960 + 57980017535961.

It is an arithmetic number, because the mean of its divisors is an integer number (57980017535961).

Almost surely, 2115960035071921 is an apocalyptic number.

It is an amenable number.

115960035071921 is a deficient number, since it is larger than the sum of its proper divisors (1).

115960035071921 is an equidigital number, since it uses as much as digits as its factorization.

115960035071921 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 510300, while the sum is 50.

The spelling of 115960035071921 in words is "one hundred fifteen trillion, nine hundred sixty billion, thirty-five million, seventy-one thousand, nine hundred twenty-one".