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115969924620241 is a prime number
BaseRepresentation
bin11010010111100101011010…
…001010010101111111010001
3120012121121122102221202001021
4122113211122022111333101
5110200022401200321431
61050351503051035441
733266356561521106
oct3227453212257721
9505547572852037
10115969924620241
1133a5162913369a
121100b8b913bb81
134c92bbc765a53
14208cd8d6a2aad
15d6199d131b11
hex69795a295fd1

115969924620241 has 2 divisors, whose sum is σ = 115969924620242. Its totient is φ = 115969924620240.

The previous prime is 115969924620227. The next prime is 115969924620247. The reversal of 115969924620241 is 142026429969511.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 109271041851841 + 6698882768400 = 10453279^2 + 2588220^2 .

It is an emirp because it is prime and its reverse (142026429969511) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 115969924620241 - 211 = 115969924618193 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 115969924620241.

It is not a weakly prime, because it can be changed into another prime (115969924620247) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57984962310120 + 57984962310121.

It is an arithmetic number, because the mean of its divisors is an integer number (57984962310121).

Almost surely, 2115969924620241 is an apocalyptic number.

It is an amenable number.

115969924620241 is a deficient number, since it is larger than the sum of its proper divisors (1).

115969924620241 is an equidigital number, since it uses as much as digits as its factorization.

115969924620241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 16796160, while the sum is 61.

The spelling of 115969924620241 in words is "one hundred fifteen trillion, nine hundred sixty-nine billion, nine hundred twenty-four million, six hundred twenty thousand, two hundred forty-one".