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11605549998473 is a prime number
BaseRepresentation
bin1010100011100010000010…
…1011110110000110001001
31112002110221201210212102122
42220320200223312012021
53010121131244422343
640403303245341025
72305321230223034
oct250704053660611
945073851725378
1011605549998473
113774982466502
121375297267775
13662524b4ca12
142c19d696a01b
15151d488c1068
hexa8e20af6189

11605549998473 has 2 divisors, whose sum is σ = 11605549998474. Its totient is φ = 11605549998472.

The previous prime is 11605549998463. The next prime is 11605549998479. The reversal of 11605549998473 is 37489994550611.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10641603049609 + 963946948864 = 3262147^2 + 981808^2 .

It is a cyclic number.

It is not a de Polignac number, because 11605549998473 - 212 = 11605549994377 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11605549998397 and 11605549998406.

It is not a weakly prime, because it can be changed into another prime (11605549998479) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5802774999236 + 5802774999237.

It is an arithmetic number, because the mean of its divisors is an integer number (5802774999237).

Almost surely, 211605549998473 is an apocalyptic number.

It is an amenable number.

11605549998473 is a deficient number, since it is larger than the sum of its proper divisors (1).

11605549998473 is an equidigital number, since it uses as much as digits as its factorization.

11605549998473 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 293932800, while the sum is 71.

The spelling of 11605549998473 in words is "eleven trillion, six hundred five billion, five hundred forty-nine million, nine hundred ninety-eight thousand, four hundred seventy-three".