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116102531103 = 3132976987977
BaseRepresentation
bin110110000100001000…
…0000000100000011111
3102002200101101200021120
41230020100000200133
53400234221443403
6125200424102023
711250062142216
oct1541020004037
9362611350246
10116102531103
1145269941049
121a602604913
13ac438b4560
14589588207d
153047c34e53
hex1b0840081f

116102531103 has 8 divisors (see below), whose sum is σ = 166711326768. Its totient is φ = 71447711424.

The previous prime is 116102531099. The next prime is 116102531113. The reversal of 116102531103 is 301135201611.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 116102531103 - 22 = 116102531099 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (116102531113) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1488493950 + ... + 1488494027.

It is an arithmetic number, because the mean of its divisors is an integer number (20838915846).

Almost surely, 2116102531103 is an apocalyptic number.

116102531103 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

116102531103 is a deficient number, since it is larger than the sum of its proper divisors (50608795665).

116102531103 is a wasteful number, since it uses less digits than its factorization.

116102531103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2976987993.

The product of its (nonzero) digits is 540, while the sum is 24.

Adding to 116102531103 its reverse (301135201611), we get a palindrome (417237732714).

The spelling of 116102531103 in words is "one hundred sixteen billion, one hundred two million, five hundred thirty-one thousand, one hundred three".

Divisors: 1 3 13 39 2976987977 8930963931 38700843701 116102531103