Base | Representation |
---|---|
bin | 1010100011111101111111… |
… | …0011111001100011010011 |
3 | 1112010012022112020220201201 |
4 | 2220333133303321203103 |
5 | 3010232012142302311 |
6 | 40410543501212031 |
7 | 2306005146155524 |
oct | 250773763714323 |
9 | 45105275226651 |
10 | 11613051525331 |
11 | 377808191a683 |
12 | 137682b561017 |
13 | 66314c0239c9 |
14 | 2c2108d5884b |
15 | 1521372559c1 |
hex | a8fdfcf98d3 |
11613051525331 has 2 divisors, whose sum is σ = 11613051525332. Its totient is φ = 11613051525330.
The previous prime is 11613051525259. The next prime is 11613051525373. The reversal of 11613051525331 is 13352515031611.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11613051525331 - 29 = 11613051524819 is a prime.
It is a super-2 number, since 2×116130515253312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11613051526331) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5806525762665 + 5806525762666.
It is an arithmetic number, because the mean of its divisors is an integer number (5806525762666).
Almost surely, 211613051525331 is an apocalyptic number.
11613051525331 is a deficient number, since it is larger than the sum of its proper divisors (1).
11613051525331 is an equidigital number, since it uses as much as digits as its factorization.
11613051525331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40500, while the sum is 37.
Adding to 11613051525331 its reverse (13352515031611), we get a palindrome (24965566556942).
The spelling of 11613051525331 in words is "eleven trillion, six hundred thirteen billion, fifty-one million, five hundred twenty-five thousand, three hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •