11613400415131 has 2 divisors, whose sum is σ = 11613400415132. Its totient is φ = 11613400415130.

The previous prime is 11613400415119. The next prime is 11613400415137. The reversal of 11613400415131 is 13151400431611.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11613400415131 - 2²¹ = 11613398317979 is a prime.

It is a super-2 number, since 2×11613400415131² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11613400415093 and 11613400415102.

It is not a weakly prime, because it can be changed into another prime (11613400415137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5806700207565 + 5806700207566.

It is an arithmetic number, because the mean of its divisors is an integer number (5806700207566).

Almost surely, 2^{11613400415131} is an apocalyptic number.

11613400415131 is a deficient number, since it is larger than the sum of its proper divisors (1).

11613400415131 is an equidigital number, since it uses as much as digits as its factorization.

11613400415131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4320, while the sum is 31.

Adding to 11613400415131 its reverse (13151400431611), we get a palindrome (24764800846742).

The spelling of 11613400415131 in words is "eleven trillion, six hundred thirteen billion, four hundred million, four hundred fifteen thousand, one hundred thirty-one".