Base | Representation |
---|---|
bin | 10000111001101110110… |
… | …101001101000111101111 |
3 | 11010001000222022111212012 |
4 | 100321232311031013233 |
5 | 123012223124023210 |
6 | 2245330325031435 |
7 | 146626032203411 |
oct | 20715665150757 |
9 | 4101028274765 |
10 | 1161500611055 |
11 | 4086538a6384 |
12 | 16913425557b |
13 | 856b53ac8a5 |
14 | 4030737c9b1 |
15 | 2032ed1e305 |
hex | 10e6ed4d1ef |
1161500611055 has 4 divisors (see below), whose sum is σ = 1393800733272. Its totient is φ = 929200488840.
The previous prime is 1161500611021. The next prime is 1161500611079. The reversal of 1161500611055 is 5501160051611.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 1161500611055 - 210 = 1161500610031 is a prime.
It is a super-2 number, since 2×11615006110552 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 116150061101 + ... + 116150061110.
It is an arithmetic number, because the mean of its divisors is an integer number (348450183318).
Almost surely, 21161500611055 is an apocalyptic number.
1161500611055 is a deficient number, since it is larger than the sum of its proper divisors (232300122217).
1161500611055 is an equidigital number, since it uses as much as digits as its factorization.
1161500611055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 232300122216.
The product of its (nonzero) digits is 4500, while the sum is 32.
Adding to 1161500611055 its reverse (5501160051611), we get a palindrome (6662660662666).
The spelling of 1161500611055 in words is "one trillion, one hundred sixty-one billion, five hundred million, six hundred eleven thousand, fifty-five".
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