Search a number
-
+
1161513033049 is a prime number
BaseRepresentation
bin10000111001101111100…
…100100101110101011001
311010001001211200121122001
4100321233210211311121
5123012234314024144
62245331451201001
7146626242611215
oct20715744456531
94101054617561
101161513033049
1140865a910196
12169138446161
13856b7b3b995
1440308c93945
1520330e74bd4
hex10e6f925d59

1161513033049 has 2 divisors, whose sum is σ = 1161513033050. Its totient is φ = 1161513033048.

The previous prime is 1161513033017. The next prime is 1161513033053. The reversal of 1161513033049 is 9403303151611.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 814268007424 + 347245025625 = 902368^2 + 589275^2 .

It is a cyclic number.

It is not a de Polignac number, because 1161513033049 - 25 = 1161513033017 is a prime.

It is a super-2 number, since 2×11615130330492 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1161513032999 and 1161513033017.

It is not a weakly prime, because it can be changed into another prime (1161513033349) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 580756516524 + 580756516525.

It is an arithmetic number, because the mean of its divisors is an integer number (580756516525).

Almost surely, 21161513033049 is an apocalyptic number.

It is an amenable number.

1161513033049 is a deficient number, since it is larger than the sum of its proper divisors (1).

1161513033049 is an equidigital number, since it uses as much as digits as its factorization.

1161513033049 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 29160, while the sum is 37.

The spelling of 1161513033049 in words is "one trillion, one hundred sixty-one billion, five hundred thirteen million, thirty-three thousand, forty-nine".