Base | Representation |
---|---|
bin | 10101101000101000… |
… | …01101100110010011 |
3 | 1002222110220211202222 |
4 | 22310110031212103 |
5 | 142241433211201 |
6 | 5200320331255 |
7 | 560555664515 |
oct | 126424154623 |
9 | 32873824688 |
10 | 11615132051 |
11 | 4a20491696 |
12 | 2301a73b2b |
13 | 11314c0a03 |
14 | 7c2875bb5 |
15 | 47ea9a91b |
hex | 2b450d993 |
11615132051 has 2 divisors, whose sum is σ = 11615132052. Its totient is φ = 11615132050.
The previous prime is 11615132047. The next prime is 11615132069. The reversal of 11615132051 is 15023151611.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11615132051 - 22 = 11615132047 is a prime.
It is a super-2 number, since 2×116151320512 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 11615132051.
It is not a weakly prime, because it can be changed into another prime (11615132251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5807566025 + 5807566026.
It is an arithmetic number, because the mean of its divisors is an integer number (5807566026).
Almost surely, 211615132051 is an apocalyptic number.
11615132051 is a deficient number, since it is larger than the sum of its proper divisors (1).
11615132051 is an equidigital number, since it uses as much as digits as its factorization.
11615132051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 900, while the sum is 26.
Adding to 11615132051 its reverse (15023151611), we get a palindrome (26638283662).
The spelling of 11615132051 in words is "eleven billion, six hundred fifteen million, one hundred thirty-two thousand, fifty-one".
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