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11626025497 is a prime number
BaseRepresentation
bin10101101001111011…
…10001001000011001
31010000020102021202221
422310331301020121
5142302230303442
65201350024041
7561050405032
oct126475611031
933006367687
1011626025497
114a26652039
122305648021
131133836138
147c40ada89
154809ed467
hex2b4f71219

11626025497 has 2 divisors, whose sum is σ = 11626025498. Its totient is φ = 11626025496.

The previous prime is 11626025459. The next prime is 11626025527. The reversal of 11626025497 is 79452062611.

11626025497 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5859749401 + 5766276096 = 76549^2 + 75936^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11626025497 is a prime.

It is not a weakly prime, because it can be changed into another prime (11626026497) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5813012748 + 5813012749.

It is an arithmetic number, because the mean of its divisors is an integer number (5813012749).

Almost surely, 211626025497 is an apocalyptic number.

It is an amenable number.

11626025497 is a deficient number, since it is larger than the sum of its proper divisors (1).

11626025497 is an equidigital number, since it uses as much as digits as its factorization.

11626025497 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 181440, while the sum is 43.

The spelling of 11626025497 in words is "eleven billion, six hundred twenty-six million, twenty-five thousand, four hundred ninety-seven".