Base | Representation |
---|---|
bin | 1010100101000101111001… |
… | …0101110101100001100110 |
3 | 1112012001010202200102002001 |
4 | 2221101132111311201212 |
5 | 3011041030140021014 |
6 | 40423455121035514 |
7 | 2310260403313624 |
oct | 251213625654146 |
9 | 45161122612061 |
10 | 11632354220134 |
11 | 378528777aa0a |
12 | 137a517a85b9a |
13 | 664c070c39cb |
14 | 2c301a7a8514 |
15 | 1528b6b82974 |
hex | a945e575866 |
11632354220134 has 4 divisors (see below), whose sum is σ = 17448531330204. Its totient is φ = 5816177110066.
The previous prime is 11632354220099. The next prime is 11632354220143. The reversal of 11632354220134 is 43102245323611.
11632354220134 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 11632354220093 and 11632354220102.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2908088555032 + ... + 2908088555035.
It is an arithmetic number, because the mean of its divisors is an integer number (4362132832551).
Almost surely, 211632354220134 is an apocalyptic number.
11632354220134 is a deficient number, since it is larger than the sum of its proper divisors (5816177110070).
11632354220134 is an equidigital number, since it uses as much as digits as its factorization.
11632354220134 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5816177110069.
The product of its (nonzero) digits is 103680, while the sum is 37.
Adding to 11632354220134 its reverse (43102245323611), we get a palindrome (54734599543745).
The spelling of 11632354220134 in words is "eleven trillion, six hundred thirty-two billion, three hundred fifty-four million, two hundred twenty thousand, one hundred thirty-four".
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