11634035332433 has 2 divisors, whose sum is σ = 11634035332434. Its totient is φ = 11634035332432.

The previous prime is 11634035332411. The next prime is 11634035332483. The reversal of 11634035332433 is 33423353043611.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5853607652929 + 5780427679504 = 2419423^2 + 2404252^2 .

It is a cyclic number.

It is not a de Polignac number, because 11634035332433 - 2¹⁰ = 11634035331409 is a prime.

It is a super-4 number, since 4×11634035332433⁴ (a number of 53 digits) contains 4444 as substring.

It is not a weakly prime, because it can be changed into another prime (11634035332483) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5817017666216 + 5817017666217.

It is an arithmetic number, because the mean of its divisors is an integer number (5817017666217).

Almost surely, 2^{11634035332433} is an apocalyptic number.

It is an amenable number.

11634035332433 is a deficient number, since it is larger than the sum of its proper divisors (1).

11634035332433 is an equidigital number, since it uses as much as digits as its factorization.

11634035332433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 699840, while the sum is 41.

The spelling of 11634035332433 in words is "eleven trillion, six hundred thirty-four billion, thirty-five million, three hundred thirty-two thousand, four hundred thirty-three".