Base | Representation |
---|---|
bin | 10101101100101100… |
… | …11011011001110101 |
3 | 1010001212011002120002 |
4 | 22312112123121311 |
5 | 142324203023232 |
6 | 5203540121045 |
7 | 561452065322 |
oct | 126626333165 |
9 | 33055132502 |
10 | 11649267317 |
11 | 4a38786a56 |
12 | 2311396185 |
13 | 11385b2cac |
14 | 7c71ddb49 |
15 | 482a8eb62 |
hex | 2b659b675 |
11649267317 has 4 divisors (see below), whose sum is σ = 12050966220. Its totient is φ = 11247568416.
The previous prime is 11649267313. The next prime is 11649267319. The reversal of 11649267317 is 71376294611.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 5546376676 + 6102890641 = 74474^2 + 78121^2 .
It is a cyclic number.
It is not a de Polignac number, because 11649267317 - 22 = 11649267313 is a prime.
It is a super-3 number, since 3×116492673173 (a number of 31 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11649267313) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 200849408 + ... + 200849465.
It is an arithmetic number, because the mean of its divisors is an integer number (3012741555).
Almost surely, 211649267317 is an apocalyptic number.
It is an amenable number.
11649267317 is a deficient number, since it is larger than the sum of its proper divisors (401698903).
11649267317 is an equidigital number, since it uses as much as digits as its factorization.
11649267317 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 401698902.
The product of its digits is 381024, while the sum is 47.
The spelling of 11649267317 in words is "eleven billion, six hundred forty-nine million, two hundred sixty-seven thousand, three hundred seventeen".
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