11655012630433 has 2 divisors, whose sum is σ = 11655012630434. Its totient is φ = 11655012630432.

The previous prime is 11655012630421. The next prime is 11655012630497. The reversal of 11655012630433 is 33403621055611.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11612439736209 + 42572894224 = 3407703^2 + 206332^2 .

It is a cyclic number.

It is not a de Polignac number, because 11655012630433 - 2¹³ = 11655012622241 is a prime.

It is not a weakly prime, because it can be changed into another prime (11655012630413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5827506315216 + 5827506315217.

It is an arithmetic number, because the mean of its divisors is an integer number (5827506315217).

Almost surely, 2^{11655012630433} is an apocalyptic number.

It is an amenable number.

11655012630433 is a deficient number, since it is larger than the sum of its proper divisors (1).

11655012630433 is an equidigital number, since it uses as much as digits as its factorization.

11655012630433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 194400, while the sum is 40.

The spelling of 11655012630433 in words is "eleven trillion, six hundred fifty-five billion, twelve million, six hundred thirty thousand, four hundred thirty-three".