11655520133 has 4 divisors (see below), whose sum is σ = 11666031180. Its totient is φ = 11645009088.

The previous prime is 11655520117. The next prime is 11655520171. The reversal of 11655520133 is 33102555611.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 33102555611 = 19 ⋅1742239769.

It can be written as a sum of positive squares in 2 ways, for example, as 5098245604 + 6557274529 = 71402^2 + 80977^2 .

It is a cyclic number.

It is not a de Polignac number, because 11655520133 - 2⁴ = 11655520117 is a prime.

It is a super-2 number, since 2×11655520133² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 11655520133.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11655520193) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5253860 + ... + 5256077.

It is an arithmetic number, because the mean of its divisors is an integer number (2916507795).

Almost surely, 2^11655520133 is an apocalyptic number.

It is an amenable number.

11655520133 is a deficient number, since it is larger than the sum of its proper divisors (10511047).

11655520133 is a wasteful number, since it uses less digits than its factorization.

11655520133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10511046.

The product of its (nonzero) digits is 13500, while the sum is 32.

The spelling of 11655520133 in words is "eleven billion, six hundred fifty-five million, five hundred twenty thousand, one hundred thirty-three".