Base | Representation |
---|---|
bin | 10101101110000000… |
… | …10011011101110101 |
3 | 1010002121210210220111 |
4 | 22313000103131311 |
5 | 142340010313403 |
6 | 5205011303021 |
7 | 561644305645 |
oct | 126700233565 |
9 | 33077723814 |
10 | 11660244853 |
11 | 4a439a45a4 |
12 | 2314baaa71 |
13 | 113a95778a |
14 | 7c885a525 |
15 | 483a0c56d |
hex | 2b7013775 |
11660244853 has 4 divisors (see below), whose sum is σ = 11661142528. Its totient is φ = 11659347180.
The previous prime is 11660244851. The next prime is 11660244877. The reversal of 11660244853 is 35844206611.
It is a happy number.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 11660244853 - 21 = 11660244851 is a prime.
It is a super-2 number, since 2×116602448532 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11660244851) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 429063 + ... + 455428.
It is an arithmetic number, because the mean of its divisors is an integer number (2915285632).
Almost surely, 211660244853 is an apocalyptic number.
It is an amenable number.
11660244853 is a deficient number, since it is larger than the sum of its proper divisors (897675).
11660244853 is an equidigital number, since it uses as much as digits as its factorization.
11660244853 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 897674.
The product of its (nonzero) digits is 138240, while the sum is 40.
The spelling of 11660244853 in words is "eleven billion, six hundred sixty million, two hundred forty-four thousand, eight hundred fifty-three".
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