Base | Representation |
---|---|
bin | 11010100001011100111000… |
… | …110110001111101100011011 |
3 | 120022000102210121222010012011 |
4 | 122201130320312033230123 |
5 | 110242130020424124334 |
6 | 1052031200552130351 |
7 | 33366352310643553 |
oct | 3241347066175433 |
9 | 508012717863164 |
10 | 116647970536219 |
11 | 341931433a7aa1 |
12 | 110bb1a93969b7 |
13 | 5011b19739215 |
14 | 20b3b12d7a163 |
15 | d74434b2a564 |
hex | 6a1738d8fb1b |
116647970536219 has 2 divisors, whose sum is σ = 116647970536220. Its totient is φ = 116647970536218.
The previous prime is 116647970536133. The next prime is 116647970536277. The reversal of 116647970536219 is 912635079746611.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 116647970536219 - 217 = 116647970405147 is a prime.
It is a super-2 number, since 2×1166479705362192 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (116647970536619) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58323985268109 + 58323985268110.
It is an arithmetic number, because the mean of its divisors is an integer number (58323985268110).
Almost surely, 2116647970536219 is an apocalyptic number.
116647970536219 is a deficient number, since it is larger than the sum of its proper divisors (1).
116647970536219 is an equidigital number, since it uses as much as digits as its factorization.
116647970536219 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 102876480, while the sum is 67.
The spelling of 116647970536219 in words is "one hundred sixteen trillion, six hundred forty-seven billion, nine hundred seventy million, five hundred thirty-six thousand, two hundred nineteen".
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