Base | Representation |
---|---|
bin | 10000111110101100011… |
… | …010111100011000011001 |
3 | 11010112210022101200201112 |
4 | 100332230122330120121 |
5 | 123104131143201213 |
6 | 2252011144230105 |
7 | 150205051563365 |
oct | 20765432743031 |
9 | 4115708350645 |
10 | 1166828881433 |
11 | 40a938536816 |
12 | 16a18076b335 |
13 | 86054256bb7 |
14 | 40690c922a5 |
15 | 205429baea8 |
hex | 10fac6bc619 |
1166828881433 has 2 divisors, whose sum is σ = 1166828881434. Its totient is φ = 1166828881432.
The previous prime is 1166828881409. The next prime is 1166828881501. The reversal of 1166828881433 is 3341888286611.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1113683417344 + 53145464089 = 1055312^2 + 230533^2 .
It is a cyclic number.
It is not a de Polignac number, because 1166828881433 - 28 = 1166828881177 is a prime.
It is a super-2 number, since 2×11668288814332 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1166828881133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 583414440716 + 583414440717.
It is an arithmetic number, because the mean of its divisors is an integer number (583414440717).
Almost surely, 21166828881433 is an apocalyptic number.
It is an amenable number.
1166828881433 is a deficient number, since it is larger than the sum of its proper divisors (1).
1166828881433 is an equidigital number, since it uses as much as digits as its factorization.
1166828881433 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 10616832, while the sum is 59.
The spelling of 1166828881433 in words is "one trillion, one hundred sixty-six billion, eight hundred twenty-eight million, eight hundred eighty-one thousand, four hundred thirty-three".
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