Base | Representation |
---|---|
bin | 1010100111010111110010… |
… | …1001000011110011001011 |
3 | 1112022210020002220001120201 |
4 | 2221311330221003303023 |
5 | 3012211231411001413 |
6 | 40453453201233031 |
7 | 2313145035663223 |
oct | 251657451036313 |
9 | 45283202801521 |
10 | 11671517281483 |
11 | 379a954258614 |
12 | 1386027632777 |
13 | 66880895c0a7 |
14 | 2c4c93b53083 |
15 | 153909e479dd |
hex | a9d7ca43ccb |
11671517281483 has 2 divisors, whose sum is σ = 11671517281484. Its totient is φ = 11671517281482.
The previous prime is 11671517281471. The next prime is 11671517281493. The reversal of 11671517281483 is 38418271517611.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11671517281483 - 225 = 11671483727051 is a prime.
It is a super-3 number, since 3×116715172814833 (a number of 40 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (11671517281453) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5835758640741 + 5835758640742.
It is an arithmetic number, because the mean of its divisors is an integer number (5835758640742).
Almost surely, 211671517281483 is an apocalyptic number.
11671517281483 is a deficient number, since it is larger than the sum of its proper divisors (1).
11671517281483 is an equidigital number, since it uses as much as digits as its factorization.
11671517281483 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2257920, while the sum is 55.
The spelling of 11671517281483 in words is "eleven trillion, six hundred seventy-one billion, five hundred seventeen million, two hundred eighty-one thousand, four hundred eighty-three".
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