Base | Representation |
---|---|
bin | 10001000000101101000… |
… | …000101100111001001001 |
3 | 11010202100122220001000201 |
4 | 101000231000230321021 |
5 | 123123040440404423 |
6 | 2253005212332201 |
7 | 150312366201034 |
oct | 21005500547111 |
9 | 4122318801021 |
10 | 1168986263113 |
11 | 4108452a7589 |
12 | 16a683174061 |
13 | 863091b5cc6 |
14 | 408175d801b |
15 | 2061c0ba2ad |
hex | 1102d02ce49 |
1168986263113 has 2 divisors, whose sum is σ = 1168986263114. Its totient is φ = 1168986263112.
The previous prime is 1168986262943. The next prime is 1168986263119. The reversal of 1168986263113 is 3113626898611.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 685777765689 + 483208497424 = 828117^2 + 695132^2 .
It is a cyclic number.
It is not a de Polignac number, because 1168986263113 - 237 = 1031547309641 is a prime.
It is not a weakly prime, because it can be changed into another prime (1168986263119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 584493131556 + 584493131557.
It is an arithmetic number, because the mean of its divisors is an integer number (584493131557).
Almost surely, 21168986263113 is an apocalyptic number.
It is an amenable number.
1168986263113 is a deficient number, since it is larger than the sum of its proper divisors (1).
1168986263113 is an equidigital number, since it uses as much as digits as its factorization.
1168986263113 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2239488, while the sum is 55.
The spelling of 1168986263113 in words is "one trillion, one hundred sixty-eight billion, nine hundred eighty-six million, two hundred sixty-three thousand, one hundred thirteen".
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