Base | Representation |
---|---|
bin | 1010101001010111010111… |
… | …1101111000110000011011 |
3 | 1112110001121220002102000011 |
4 | 2222111311331320300123 |
5 | 3013241401322223011 |
6 | 40521315413422351 |
7 | 2315466525061162 |
oct | 252256575706033 |
9 | 45401556072004 |
10 | 11705765039131 |
11 | 3803429217859 |
12 | 13907a503a9b7 |
13 | 66bb06081747 |
14 | 2c67c23a63d9 |
15 | 154761936621 |
hex | aa575f78c1b |
11705765039131 has 2 divisors, whose sum is σ = 11705765039132. Its totient is φ = 11705765039130.
The previous prime is 11705765039057. The next prime is 11705765039149. The reversal of 11705765039131 is 13193056750711.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11705765039131 - 29 = 11705765038619 is a prime.
It is a super-2 number, since 2×117057650391312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11705765039431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5852882519565 + 5852882519566.
It is an arithmetic number, because the mean of its divisors is an integer number (5852882519566).
Almost surely, 211705765039131 is an apocalyptic number.
11705765039131 is a deficient number, since it is larger than the sum of its proper divisors (1).
11705765039131 is an equidigital number, since it uses as much as digits as its factorization.
11705765039131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 595350, while the sum is 49.
The spelling of 11705765039131 in words is "eleven trillion, seven hundred five billion, seven hundred sixty-five million, thirty-nine thousand, one hundred thirty-one".
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