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117104146673 is a prime number
BaseRepresentation
bin110110100001111110…
…0110111100011110001
3102012021012010000112112
41231003330313203301
53404312130143143
6125444044135105
711313643552223
oct1550374674361
9365235100475
10117104146673
1145733268708
121a841b37495
13b073268ba7
14594c8d0413
1530a5b34e18
hex1b43f378f1

117104146673 has 2 divisors, whose sum is σ = 117104146674. Its totient is φ = 117104146672.

The previous prime is 117104146637. The next prime is 117104146699. The reversal of 117104146673 is 376641401711.

Together with previous prime (117104146637) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 78225377344 + 38878769329 = 279688^2 + 197177^2 .

It is a cyclic number.

It is not a de Polignac number, because 117104146673 - 218 = 117103884529 is a prime.

It is a super-2 number, since 2×1171041466732 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 117104146673.

It is not a weakly prime, because it can be changed into another prime (117104146273) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58552073336 + 58552073337.

It is an arithmetic number, because the mean of its divisors is an integer number (58552073337).

Almost surely, 2117104146673 is an apocalyptic number.

It is an amenable number.

117104146673 is a deficient number, since it is larger than the sum of its proper divisors (1).

117104146673 is an equidigital number, since it uses as much as digits as its factorization.

117104146673 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 84672, while the sum is 41.

The spelling of 117104146673 in words is "one hundred seventeen billion, one hundred four million, one hundred forty-six thousand, six hundred seventy-three".