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1171220503841 is a prime number
BaseRepresentation
bin10001000010110010001…
…011101001110100100001
311010222010101000020010022
4101002302023221310201
5123142124422110331
62254015024043225
7150421636010303
oct21026213516441
94128111006108
101171220503841
11411791493723
1216aba7463515
13865a404593b
144098a229973
15206ed2ec67b
hex110b22e9d21

1171220503841 has 2 divisors, whose sum is σ = 1171220503842. Its totient is φ = 1171220503840.

The previous prime is 1171220503837. The next prime is 1171220503907. The reversal of 1171220503841 is 1483050221711.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1159627459600 + 11593044241 = 1076860^2 + 107671^2 .

It is a cyclic number.

It is not a de Polignac number, because 1171220503841 - 22 = 1171220503837 is a prime.

It is not a weakly prime, because it can be changed into another prime (1171220503441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 585610251920 + 585610251921.

It is an arithmetic number, because the mean of its divisors is an integer number (585610251921).

Almost surely, 21171220503841 is an apocalyptic number.

It is an amenable number.

1171220503841 is a deficient number, since it is larger than the sum of its proper divisors (1).

1171220503841 is an equidigital number, since it uses as much as digits as its factorization.

1171220503841 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13440, while the sum is 35.

The spelling of 1171220503841 in words is "one trillion, one hundred seventy-one billion, two hundred twenty million, five hundred three thousand, eight hundred forty-one".