Base | Representation |
---|---|
bin | 10101110100010011… |
… | …00001000111101011 |
3 | 1010020022001122000021 |
4 | 22322021201013223 |
5 | 142442011213343 |
6 | 5214134021311 |
7 | 563154533626 |
oct | 127211410753 |
9 | 33208048007 |
10 | 11712991723 |
11 | 4a70751054 |
12 | 232a7a7837 |
13 | 1148865244 |
14 | 7d186adbd |
15 | 48847b0ed |
hex | 2ba2611eb |
11712991723 has 2 divisors, whose sum is σ = 11712991724. Its totient is φ = 11712991722.
The previous prime is 11712991673. The next prime is 11712991727. The reversal of 11712991723 is 32719921711.
11712991723 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11712991723 - 221 = 11710894571 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11712991723.
It is not a weakly prime, because it can be changed into another prime (11712991727) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5856495861 + 5856495862.
It is an arithmetic number, because the mean of its divisors is an integer number (5856495862).
Almost surely, 211712991723 is an apocalyptic number.
11712991723 is a deficient number, since it is larger than the sum of its proper divisors (1).
11712991723 is an equidigital number, since it uses as much as digits as its factorization.
11712991723 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 47628, while the sum is 43.
The spelling of 11712991723 in words is "eleven billion, seven hundred twelve million, nine hundred ninety-one thousand, seven hundred twenty-three".
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