Base | Representation |
---|---|
bin | 10101110100010110… |
… | …11011011000000001 |
3 | 1010020100000001220212 |
4 | 22322023123120001 |
5 | 142442123224411 |
6 | 5214152443505 |
7 | 563162020565 |
oct | 127213333001 |
9 | 33210001825 |
10 | 11713492481 |
11 | 4a70a632a9 |
12 | 232a9a9595 |
13 | 11489ac152 |
14 | 7d195b6a5 |
15 | 48852968b |
hex | 2ba2db601 |
11713492481 has 2 divisors, whose sum is σ = 11713492482. Its totient is φ = 11713492480.
The previous prime is 11713492409. The next prime is 11713492513. The reversal of 11713492481 is 18429431711.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11667456256 + 46036225 = 108016^2 + 6785^2 .
It is a cyclic number.
It is not a de Polignac number, because 11713492481 - 210 = 11713491457 is a prime.
It is a super-2 number, since 2×117134924812 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11713422481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5856746240 + 5856746241.
It is an arithmetic number, because the mean of its divisors is an integer number (5856746241).
Almost surely, 211713492481 is an apocalyptic number.
It is an amenable number.
11713492481 is a deficient number, since it is larger than the sum of its proper divisors (1).
11713492481 is an equidigital number, since it uses as much as digits as its factorization.
11713492481 is an evil number, because the sum of its binary digits is even.
The product of its digits is 48384, while the sum is 41.
The spelling of 11713492481 in words is "eleven billion, seven hundred thirteen million, four hundred ninety-two thousand, four hundred eighty-one".
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