117140111153343 has 16 divisors (see below), whose sum is σ = 173544917702400. Its totient is φ = 78091601905080.

The previous prime is 117140111153321. The next prime is 117140111153347. The reversal of 117140111153343 is 343351111041711.

117140111153343 is a `hidden beast` number, since 1 + 1 + 7 + 1 + 4 + 0 + 1 + 111 + 533 + 4 + 3 = 666.

It is not a de Polignac number, because 117140111153343 - 2¹⁴ = 117140111136959 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 117140111153298 and 117140111153307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (117140111153347) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 48963673 + ... + 51300306.

It is an arithmetic number, because the mean of its divisors is an integer number (10846557356400).

Almost surely, 2^{117140111153343} is an apocalyptic number.

117140111153343 is a deficient number, since it is larger than the sum of its proper divisors (56404806549057).

117140111153343 is a wasteful number, since it uses less digits than its factorization.

117140111153343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 100307259 (or 100307253 counting only the distinct ones).

The product of its (nonzero) digits is 15120, while the sum is 36.

The spelling of 117140111153343 in words is "one hundred seventeen trillion, one hundred forty billion, one hundred eleven million, one hundred fifty-three thousand, three hundred forty-three".