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117140111153321 is a prime number
BaseRepresentation
bin11010101000100111001110…
…101101101101100010101001
3120100202111002202100210221012
4122220213032231231202221
5110323210421423401241
61053045231341353305
733450044104113404
oct3250471655554251
9510674082323835
10117140111153321
1134362929a00823
121117a656268835
13504935a509069
1420cd87c45ad3b
15d8213a78c6eb
hex6a89ceb6d8a9

117140111153321 has 2 divisors, whose sum is σ = 117140111153322. Its totient is φ = 117140111153320.

The previous prime is 117140111153239. The next prime is 117140111153347. The reversal of 117140111153321 is 123351111041711.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 100873900960000 + 16266210193321 = 10043600^2 + 4033139^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-117140111153321 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (117140111153381) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 58570055576660 + 58570055576661.

It is an arithmetic number, because the mean of its divisors is an integer number (58570055576661).

Almost surely, 2117140111153321 is an apocalyptic number.

It is an amenable number.

117140111153321 is a deficient number, since it is larger than the sum of its proper divisors (1).

117140111153321 is an equidigital number, since it uses as much as digits as its factorization.

117140111153321 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2520, while the sum is 32.

The spelling of 117140111153321 in words is "one hundred seventeen trillion, one hundred forty billion, one hundred eleven million, one hundred fifty-three thousand, three hundred twenty-one".