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11714113 = 53221021
BaseRepresentation
bin101100101011…
…111001000001
3211001010202001
4230223321001
510444322423
61055024001
7201365635
oct54537101
924033661
1011714113
116680a94
123b0b001
132571b38
1417acdc5
151065cad
hexb2be41

11714113 has 4 divisors (see below), whose sum is σ = 11935188. Its totient is φ = 11493040.

The previous prime is 11714111. The next prime is 11714117. The reversal of 11714113 is 31141711.

It is a happy number.

11714113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 10679824 + 1034289 = 3268^2 + 1017^2 .

It is a cyclic number.

It is not a de Polignac number, because 11714113 - 21 = 11714111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11714111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 110458 + ... + 110563.

It is an arithmetic number, because the mean of its divisors is an integer number (2983797).

Almost surely, 211714113 is an apocalyptic number.

It is an amenable number.

11714113 is a deficient number, since it is larger than the sum of its proper divisors (221075).

11714113 is an equidigital number, since it uses as much as digits as its factorization.

11714113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 221074.

The product of its digits is 84, while the sum is 19.

The square root of 11714113 is about 3422.5886401962. The cubic root of 11714113 is about 227.1101110825.

Adding to 11714113 its reverse (31141711), we get a palindrome (42855824).

The spelling of 11714113 in words is "eleven million, seven hundred fourteen thousand, one hundred thirteen".

Divisors: 1 53 221021 11714113